Question

АЛГЕБРА 8 КЛАСС Ф.О СРОЧНОО 80 БАЛЛОВ!!!!

Answer 1

$1. \frac{\sqrt{3}(1-\sqrt{3}) }{\sqrt{3} } =1-\sqrt{3}\\2. \sqrt{\frac{\sqrt{(113-112)(113+112)}}{(19-11)(19+11)} }=\sqrt{\frac{\sqrt{225} }{8*30} } =\sqrt{\frac{15}{240} }=\sqrt{\frac{1}{16} } =\frac{1}{4}\\\\3. \sqrt{25}<\sqrt{31}<\sqrt{36}, 5<5,6<6, \sqrt{31}=5,6\\ \sqrt{31}-3=5,6-3=2,6\\4. \sqrt{3,61x^10y^6}=\sqrt{3,61}*\sqrt{x^10}*\sqrt{y^6}=1,9x^5y^3\\5. 2\sqrt{3*27}-6\sqrt{2*18}=2\sqrt{81}-6\sqrt{36}=2*9-6*6=18-36=-18\\\\\sqrt{5^6}*\sqrt{4^2}=5^3*4=500$

$\sqrt{\frac{242}{2} }-7=\sqrt{121}-7=11-7=4\\\sqrt{(-47)^2}=\sqrt{47^2}=47$