Question

a straight line passes through two points with co-ordinates (6, 8) and (0, 5).
work out the equation of the line.​

Answer 1

Ответ:

x - 2y + 10 = 0

Пошаговое объяснение:

Let (x1;y1) = (6;8), (x2;y2) = (0;5)

Using the formula: $\frac{x-x_{1} }{x_{2}-x_{1}} = \frac{y-y_{1}}{y_{2}-y_{1}}$

Convert it: $(x_{2}-x_{1})(y-y_{1}) = (y_{2}-y_{1})(x-x_{1})$

Substitute the values: (0 - 6)(y - 8) = (5 - 8)(x - 6);

-6(y - 8) = -3(x - 6)

-6y + 48 = -3x + 18

3x - 6y + 30 = 0

x - 2y + 10 = 0