Question

-а^6+1/8 ввиде разности кубов

Answer 1

-a⁶+(1/8)=(1/8)-a⁶=(1/2)³-(a²)³=((1/2)-a²)*((1/2)²+(1/2)*a²+a⁴)=

=((1/2)-a²)*((1/4)+(a²/2)+a⁴).