Question

a)3a(a-2)–2a(a-3)
б)5b(b-c)+c(2b-c)

Answer 1

a)3a(a-2)–2a(a-3)=3а2-6а-2а2+6а=а2
б)5b(b-c)+c(2b-c)=5б2-5бс+2бс-с2=5б2-3бс-с2

Answer 2

спасибо!

Answer 3

$rm 3a(a-2)-2a(a-3)= 3a^2 - 6a - 2a^2 + 6a = a^2 \ \ 5b(b - c) +c(2b - c) = 5b^2 - 5bc + 2bc - c^2 = 5b^2 - c^2 - 3bc$