Question

а) 2sin6,5П-√3sin 19П/3

Answer 1

2sin(6π+0,5π)-√3sin(6π+π/3)=2sinπ/2-√3sinπ/3=2*1-√3*√3/2=
=2-1,5=0,5

Answer 2

2.sin 6,5pí-V3(sin19pí/3)=2.sin 0,5pí -V3(sinpí/3)=2.0-V3.V3/2=
=0-3/2=-3/2=-1,5