Question

9p^2-4 как решить?
1/36-c^2
4x-y2
36x^2-25y^2
A^2b^2-9

Answer 1

$9 p^{2} -4=(3p) ^{2} -2 ^{2} =(3p-2)(3p+2)\\ frac{1}{36}- c^{2} =( frac{1}{6}) ^{2}- c^{2}=( frac{1}{6}-c)( frac{1}{6} +c)\\36 x^{2} -25 y^{2}=(6x) ^{2}-(5y) ^{2}=(6x-5y)(6x+5y)\\ a^{2} b^{2}-9=(ab) ^{2}-3 ^{2}=(ab-3)(ab+3)$