(³√9+³√6+³√4)*(³√3-³√2) решите
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Ответил kirichekov
0
1. разность кубов:
a³-b³=(a-b)*(a²+ab+b²)
2. (∛a)³=a
3.![(sqrt[3]{9} + sqrt[3]{6}+ sqrt[3]{4})*( sqrt[3]{3}- sqrt[3]{2} ) =( sqrt[3]{ 3^{2} }+ sqrt[3]{3*2}+ sqrt[3]{ 2^{2} } )*( sqrt[3]{3}- sqrt[3]{2} )=](https://tex.z-dn.net/?f=+%28sqrt%5B3%5D%7B9%7D+%2B+sqrt%5B3%5D%7B6%7D%2B+sqrt%5B3%5D%7B4%7D%29%2A%28+sqrt%5B3%5D%7B3%7D-+sqrt%5B3%5D%7B2%7D++%29++%3D%28+sqrt%5B3%5D%7B+3%5E%7B2%7D+%7D%2B+sqrt%5B3%5D%7B3%2A2%7D%2B+sqrt%5B3%5D%7B+2%5E%7B2%7D+%7D+++%29%2A%28+sqrt%5B3%5D%7B3%7D-+sqrt%5B3%5D%7B2%7D++%29%3D "(sqrt[3]{9} + sqrt[3]{6}+ sqrt[3]{4})*( sqrt[3]{3}- sqrt[3]{2} ) =( sqrt[3]{ 3^{2} }+ sqrt[3]{3*2}+ sqrt[3]{ 2^{2} } )*( sqrt[3]{3}- sqrt[3]{2} )=")
![=(( sqrt[3]{3} )^{2}+ sqrt[3]{3}* sqrt[3]{2}+( sqrt[3]{2} )^{2} )*(sqrt[3]{3}- sqrt[3]{2})=( sqrt[3]{3} ) ^{3}-( sqrt[3]{2} )^{3} =](https://tex.z-dn.net/?f=%3D%28%28+sqrt%5B3%5D%7B3%7D+%29%5E%7B2%7D%2B+sqrt%5B3%5D%7B3%7D%2A+sqrt%5B3%5D%7B2%7D%2B%28+sqrt%5B3%5D%7B2%7D+%29%5E%7B2%7D+%29%2A%28sqrt%5B3%5D%7B3%7D-+sqrt%5B3%5D%7B2%7D%29%3D%28+sqrt%5B3%5D%7B3%7D+%29+%5E%7B3%7D-%28+sqrt%5B3%5D%7B2%7D+%29%5E%7B3%7D+%3D "=(( sqrt[3]{3} )^{2}+ sqrt[3]{3}* sqrt[3]{2}+( sqrt[3]{2} )^{2} )*(sqrt[3]{3}- sqrt[3]{2})=( sqrt[3]{3} ) ^{3}-( sqrt[3]{2} )^{3} =")
=3-2=1
a³-b³=(a-b)*(a²+ab+b²)
2. (∛a)³=a
3.
=3-2=1
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