Question

9^3-log3 5^4 + 7^-log7 2

Answer 1

9^(3-log₃ 5^4) + 7^-log₇ 2 =(3²)^(3 -log₃5^4) + (7^log₇2)^-1 =
=3^6 * 3^-2log₃5^4 + 2^-1 = 3^6 * (3^log₃5^4)^-2 + 1/2 =
=3^6 *5^-8 +1/2 = 729/380625 +1/2