Question

8x-x²=0


(3-x)(2x-4) - (2x-4)(5+x)=0

Answer 1

Ответ:

8х-х²=0

х(8-х)=0

х=0 8-х=0

х=8

(3-х)(2х-4)-(2х-4)(5+х)=0

(2х-4)(3-х-(5+х))=0

(2х-4)(3-х-5-х)=0

(2х-4)(-2-2х)=0

2х-4=0 -2-2х=0

х=2 х=-1