Question

8x^2-12=3(x-4)

Помогите пожалуйстa

Answer 1

Ответ:

$8 {x}^{2} - 12 = 3(x - 4) \\ 8 {x}^{2} - 12 = 3x - 12 \\ 8 {x}^{2} = 3x \\ 8 {x}^{2} - 3x = 0 \\ x(8x - 3) = 0 \\ \\ x = 0 \\ 8x - 3 = 0 \\ \\ x1 = 0 \\ x2 = \frac{3}{8}$

Answer 2

Ответ:

$0, \quad \frac{3}{8};$

Объяснение:

$8x^{2}-12=3(x-4);$

$8x^{2}-12=3x-12;$

$8x^{2}-3x=12-12;$

$x(8x-3)=0;$

$x=0 \quad \vee \quad 8x-3=0;$

$x=0 \quad \vee \quad 8x=3;$

$x=0 \quad \vee \quad x=\frac{3}{8};$