Question

(8х-3)/7-(3х+1)/10=2 помогите решить :*

Answer 1

$frac{(8x-3)}{7} - frac{(3x+1)}{10} =2 \ \ 10(8x-3)-7(3x+1)=140 \ 80x-30-21x-7=140 \ 59x-30-7=140 \ 59x-37=140 \ 59x=140+37 \ 59x=177 \ x=177:59 \ x=3$