Question

(6x-7):7-3=(5x-3):8
gпомогите решить

Answer 1

$\frac{6x-7}{7} -3= \frac{5x-3}{8} \\ \\ \frac{6x-28}{7}= \frac{5x-3}{8} \\ 8(6x-28)=7(5x-3) \\ 48x-224=35x-21 \\ 48x-35x=224-21 \\ 13x=203 \\ x=15 \frac{8}{13}$