Question

5sin(-п/3)+2cos(-п/3)/cos(-п/2)+sin3п/2

Answer 1

$5, sin(-frac{pi}{3})+2, cos(-frac{pi}{3})cdot cos(-frac{pi}{2})+sinfrac{3pi }{2}=\\=-5cdot sinfrac{pi }{3}+2, cosfrac{pi }{3}cdot cosfrac{pi }{2}+(-1)=\\=-5cdot frac{sqrt3}{2}+2cdot frac{1}{2}cdot 0-1=-frac{5sqrt3}{2}-1=-frac{5sqrt3+2}{2}$