Question

5cos(3x-2)-4=0 решение​

Answer 1

$5 cos(3x - 2) - 4 = 0 \ cos(3x - 2) = frac{4}{5} \ 3x - 2 = ± arccos frac{4}{5} + 2pi n \ 3x = ± arccosfrac{4}{5}+ 2 + 2pi n \ x = ±frac{1}{3} arccos frac{4}{5} + frac{2}{3} + frac{2pi}{3} n, : n in Z$