Question

5(8z-1)-7(4z+1)+8(7-4z)=9

Answer 1

40z-5-28z-7+56-32z=9
40z-28z-32z=9+5+7-56
-20z=-35
z=-35÷(-20)
z=$frac{35}{20}$=$1 frac{3}{4}$