Question

4x ^ 2 = (2x + 3)(x - 4) + 6x + 13

Answer 1

Ответ:

x1=1

x2=-0.5

4x ^ 2 = (2x + 3)(x - 4) + 6x + 13

4x² = 2x²+3x-8x-12 +6x+13

2x²-x-1=0

d=1+4*2*1=9

x1=(1+√9)/4 = 4/4=1

x2=(1-√9)/4 = -2/4=-0.5