Question

4а(а-2)-(а-4) в квадрате

Answer 1

4*a*(a-2)-(a-4)^2=(4*a-8)*a-(a-4)^2=4*a^2-8*a-(a-4)^2=4*a^2-8*a-a^2+8*a-16= 3*a^2-8*a+8*a-16=3*a^2-16