Question

47а2b4 — 8аb3 + 3а2b­ — 45а2b4 + 6аb3 при а = 2, b =-3.

Answer 1

$47 {a}^{2} {b}^{4} - 8 {ab}^{3} + 3 {a}^{2} b - 45 {a}^{2} {b}^{4} \ + 6 {ab}^{3} = 2 {a}^{2} {b}^{4} - 2 {ab}^{3} + 3 {a}^{2} b = \ 2 times 4 times 81 - 4 times ( - 27) - 36 =$

$648 +10 8 - 36 = 723$

Вроде так