Question

4^х+2^+1-8=0 решение

Answer 1

4^x+2^(x+1)-8=0
4^x+2^x *2¹-8=0
4^x+2*2^x-8=0
(2^x)²+2*2^x-8=0
2^x=t, t>0
t²+2t-8=0
t₁=2, t₂=-4, -4<0
t=2
2^x=2, 2^x=2¹
x=1