Question

4)(1 + y)3+ (1 - y)3 – 6y2 = 3y -1​

Answer 1

(1+y)^3+(1+y)^3-6y^2=3y-1

1+3y+3y^3+y^3+1-3y+3y^2-y^3-6y=3y-1

1+3y^2+1-3y+3y^2-6y^2=-1

2+0-3y=-1

2-3y=-1

-3y=-1-2

-3y=-3

y=1

Answer 2

Ответ:

y=7/15

Объяснение:

(1+y)3+(1-y)3-6y2=3y-1

3+3y+3-3y-12y=3y-1

3y-3y-12y-3y=-1-3-3

-15y=-7

y=7/15