Question

3x(2+x)-4(1-x•4)=7x•4+6x. Срочно помогите!!!

Answer 1

3x(2 + x) - 4(1 - x * 4) = 7x * 4 + 6x

6x + 3x² - 4 + 16x = 28x + 6x

3x² + 16x - 28x - 4 = 0

3x² - 12x - 4 = 0

D = (- 12)² - 4 * 3 * ( - 4) = 144 + 48 = 192

$x_{1}=frac{12+sqrt{192}}{6}=frac{12+8sqrt{3}}{6}=frac{6+4sqrt{3}}{3}\\x_{2}=frac{12-sqrt{192} }{6}=frac{12-8sqrt{3}}{6}=frac{6-4sqrt{3}}{3}$

Answer 2

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Answer 3

Спасибо