Question

3b^2-3/1-b * b/b+1 помогите

Answer 1

$frac{3b^2-3}{1-b}* frac{b}{b+1}= frac{3(b^2-1)}{1-b}*frac{b}{b+1}= frac{3(b-1)(b+1)}{1-b}*frac{b}{b+1}= frac{3b(b-1)(b+1)}{(1-b)(b+1)}=$
$=frac{3b(b-1)}{1-b}=-frac{3b(b-1)}{b-1}=-3b$