Question

3а-3b/3a² × a⁴/a²-b²
Помогите пж!​

Answer 1

$frac{3a-3b}{3a^2} *frac{a^4}{a^2-b^2} =frac{3*(a-b)}{3*a^2} *frac{a^4}{(a-b)*(a+b)} =\\=frac{3*(a-b)*a^2*a^2}{3*a^2*(a-b)(a+b)} =frac{a^2}{a+b}, if aneq0 and aneq-b$