35 баллов срочно посчитайте
2пи-пи/3
-пи-(-пи/3)
пи-(-пи/3)
Ответы на вопрос
Ответил egorivashkin2
0
2π-π/3=(6π-π)/3=5π/3
-π-(-π/3)= -π+π/3=(-3π+π)/3=-2π/3
π-(-π/3)=π+π/3=(3π+π)/3=4π/3
-π-(-π/3)= -π+π/3=(-3π+π)/3=-2π/3
π-(-π/3)=π+π/3=(3π+π)/3=4π/3
Ответил innuusskaa
0
2π-π/3=(6π-π)/3=5π/3
-π-(-π/3)= -π+π/3=(-3π+π)/3=-2π/3
π-(-π/3)=π+π/3=(3π+π)/3=4π/3
-π-(-π/3)= -π+π/3=(-3π+π)/3=-2π/3
π-(-π/3)=π+π/3=(3π+π)/3=4π/3
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