Question

3)(xy-2x+y)*3+2(2xy+3x-6y),если x=1 2/3,y=-5/6

Answer 1

$(xy-2x+y)*3+2(2xy+3x-6y)=3xy-6x+3y+4xy+6x-12y$
$=7xy-9y=y(7x-9)$
$-frac{5}{6}(7*1 frac{2}{3}-9)= -frac{5}{6}(frac{35-27}{3})=-frac{5}{6}*frac{8}{3}=-frac{40}{18}=-2frac{2}{9}$