Question

3 log3 2 - log3 24 + log2 27

Answer 1

$3log_{3}2-log_{3}24+log_{3}27=log_{3}2^{3} -log_{3}24+log_{3}27= \\ =log_{3}8-log_{3}24+log_{3}27=log_{3}\frac{8*27}{24}=log_{3}9=2$