Question

3 х + 4 x^2
________ = 0
x-1
x^2 -4x
______=0
x+3
9-x^2
_____=0
x+3
36x^2-1
______=0
1-6x

Answer 1

$frac{3x+4x^2}{x-1} =0 \ frac{x(3+4x)}{x-1}=0 \ left { {{x(3+4x)=0} atop {x-1 neq 0}} right. \ left { {{x=0, x= - frac{3}4} } atop {x neq 1}} right.$
------------------
$frac{x^2-4x}{x+3} =0 \ frac{x(x-4)}{x+3}=0 \ left { {{x(x-4)=0} atop {x+3 neq 0}} right. \ left { {{x=0, x=4} atop {x neq -3}} right.$
------------------
$frac{9-x^2}{x+3}=0 \ frac{(3-x)(3+x)}{x+3} =0 \ 3-x=0 \ x=-3$
------------------
$frac{36x^2-1}{1-6x}=0 \ frac{(6x-1)(6x+1)}{1-6x}=0 \ -frac{(6x-1)(6x+1)}{6x-1}=0 \ -6x+1=0 \ 6x-1=0 \ 6x=1 \ x= frac{1}{6}$
Надеюсь я правильно вас поняла.