3 arcsin 1/2+4 arccos(-1/2)-arctg(-√3)
Ответы на вопрос
Ответил nKrynka
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Решение
3 arcsin 1/2+4 arccos(-1/2)-arctg(-√3) = 3*(π/6) + 4*(2π/3) - 2π/3 =
= π/2 + 8π/3 - 2π/3 = π/2 + 2π = 5π/2
3 arcsin 1/2+4 arccos(-1/2)-arctg(-√3) = 3*(π/6) + 4*(2π/3) - 2π/3 =
= π/2 + 8π/3 - 2π/3 = π/2 + 2π = 5π/2
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