Question

(3 7/12 - 2 13/24) * 4/5 + (4 1/18 - 3 7/12) * 6/17

Answer 1

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Answer 2

$(3frac{7}{12}-2frac{13}{24})cdotfrac{4}{5}+(4frac{1}{18}-3frac{7}{12})cdotfrac{6}{17}=1$

 

1) $3frac{7}{12}-2frac{13}{24}=frac{43}{12}-frac{61}{24}=frac{86-61}{24}=frac{25}{24}=1frac{1}{24}$

 

2) $4frac{1}{18}-3frac{7}{12}=frac{73}{18}-frac{43}{12}=frac{146-129}{36}=frac{17}{36}$

 

3) $1frac{1}{24}cdotfrac{4}{5}=frac{25}{24}cdotfrac{4}{5}=frac{5}{6}$

 

4) $frac{17}{36}cdotfrac{6}{17}=frac{1}{6}$

 

5) $frac{5}{6}+frac{1}{6}=frac{5+1}{6}=frac{6}{6}=1$