Question

(3,5 - х) (4х+1) + (2х+3) ^2 <0 ,, пж помогите

Answer 1

$mathtt{(3,5-x)(4x+1)+(2x+3)^2 textless 0;~2(2x+3)^2-(2x-7)(4x+1) textless 0;~}\mathtt{2(4x^2+12x+9)-(8x^2-26x-7) textless 0;~}\mathtt{8x^2+24x+18-8x^2+26x+7 textless 0;~50x+25 textless 0;~x textless -frac{25}{50}}$

ОТВЕТ: $mathtt{x textless -frac{1}{2}}$