Question

-3-3(3-2x)=1 ...........................

Answer 1

$displaystyle tt -3-3(3-2x)=1\displaystyle tt -3-3cdot3-3cdot(-2x)=1\displaystyle tt -3-9+6x=1\displaystyle tt -12+6x=1\displaystyle tt 6x=1+12\displaystyle tt 6x=13\displaystyle tt x=13div6\\ displaystyle tt bold{x=2frac{1}{6}}$