Question

㏒₂(ײ+3×)=2 помогитееее

Answer 1

$log_{2}( {x}^{2} + 3x) = 2 \ {x}^{2} + 3x = 4 \ {x}^{2} + 3x - 4 = 0 \ (x + 4)(x - 1) = 0 \ x = - 4 \ x = 1 \ {x}^{2} + 3x > 0 \ x(x + 3) > 0 \ x = 1 \ x = - 4$