Question

(2y-3)(3y+1)+2(y-5)(y+5)=2(1-2y)^2+6y

Answer 1

$(2y-3)(3y+1)+2(y-5)(y+5)=2(1-2y)^2+6y 6y^2+2y-9y-3+2(y^2-25)=2(1-4y+4y^2)+6y 6y^2+2y-9y-3+2y^2-50=2-8y+8y^2+6y 8y^2-7y-53=2-2y+8y^2 -7y-53=2-2y+8y^2 -7y+2y=2+53 -5y=55 y=55:-5 y=-11$