Question

(2xy-2xy)÷xy/x^2-y^2
решите пж​

Answer 1

(2xy-2xy)÷xy/x^2-y^2

(2xy-2xy)

0÷xy/x^2-y^2

xy/x^2-y^2(x+y)(x-y)xy/[(x+y)(x-y)]

0÷[xy/((x+y)(x-y))]

0 * ((x+y)(x-y))/xy

0 (2xy-2xy)÷xy/x^2-y^2 = 0