Алгебра, вопрос задал Nobody0808 , 7 лет назад

2x(x−26)2−x2(x−26)=0

Ответы на вопрос

Ответил elenamuraweva
0

Ответ:

2x(x - 26)2 -  {x}^{2} (x - 26) = 0 \\ 4x(x - 26)  -  {x}^{3}   + 26 {x}^{2}  = 0 \\ 4 {x}^{2}  - 104x -  {x}^{3}  + 26 {x}^{2}  = 0 \\  -  {x}^{3}  + 30 {x}^{2}  - 104x = 0 \\  - x( {x}^{2}  - 30x + 104) = 0 \\ 1) - x = 0 \\ x = 0 \\ 2) {x}^{2}  - 30x + 104 = 0 \\ d =  {b}^{2}  - 4ac =  {( - 30)}^{2}  - 4 \times 1 \times  104 = 900 - 416 = 484 \\ x1 =  \frac{ -b -  \sqrt{d} }{2a}  =  \frac{ - ( - 30) -  \sqrt{484} }{2 \times 1}  =  \frac{30 - 22}{2}  =  \frac{8}{2}  = 4 \\ x2 = \frac{ -b  +  \sqrt{d} }{2a}  =  \frac{ - ( - 30)  +   \sqrt{484} }{2 \times 1}  =  \frac{30  +  22}{2}  =  \frac{52}{2}  = 26

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