Question

2x^2+x-1/x^2-1=0
Решите пожалуйста

Answer 1

$\frac{2x^2+x-1}{x^2-1} = 0, ~~x\neq -1, x\neq 1\\\frac{2x^2+2x-x-1}{(x-1)(x+1)} = 0\\\frac{2x(x+1)-(x+1)}{(x-1)(x+1)} = 0\\\frac{(x+1)(2x-1)}{(x-1)(x+1)} = 0\\\frac{2x-1}{x-1}=0\\2x-1=0\\2x=1\\x=\frac{1}{2} = 0.5$