Question

(2x-1)^2=2x-1
1/5x^2-5=0

Answer 1

$(2x - 1) {}^{2} = 2x - 1 \ 2x times (2x - 1) { }^{2} - 1 \ 2x times (4x {}^{2} - 4x + 1) - 1 \ 8x {}^{3} - 8x {}^{2} + 2x - 1. \ \ frac{1}{5} x {}^{2} - 5 = 0 \ \ x {}^{2} - 25 = 0 \ x {}^{2} - 25 + 25 = 0 + 25 \ x {}^{2} = 0 + 25 \ x {}^{2} = 25 \ x = 5 \ x = - 5 \ x {}^{1} = - 5 \ x {}^{2} = 5$