Question

2sinx -√3 tgx - 2√3 cosx+3=0

Answer 1

2sinx -√3 tgx - 2√3 cosx+3=0

2sinxcosx-sqrt(3)sinx-2sqrt(3)*cos^2x+3cosx=0

sinx(2cosx-sqrt(3))-cosx*sqrt(3)(2cosx-sqrt(3))=0

(2cosx-sqrt(3))(sinx-cosx*sqrt(3))=0

cosx=sqrt(3)/2           sinx-sqrt(3)cosx=0  tgx=sqrt(3)

x=+-П/6+2Пk                                              x=П/3+Пk