Question

2sin²x=√3cos(3π/2+x)

Answer 1

2sin²x=√3cos(3π/2+x)
2sin²x=√3sinx
2sin²x - √3sinx= 0
sinx (2sinx - √3) = 0

sinx = 0 ==>
 x = pik, k∈Z

sinx = √3/2 ==>
x = pi/3 + 2pik, k ∈Z
x = 2pi/3 + 2pik, k ∈Z

Answer 2

да

Answer 3

формулы приведения открой