Question

2sin x/2 = 1-cosx

Answer 1

1-cosx=2*sin(x2) 
2sin²(x/2)-2sin(x/2)=0 
sin(x/2)(sin(x/2)-1)=0 
a) sin(x/2)=0 
x/2=πn 
x1=2πn 
б) 
sin(x/2)-1=0 
sin(x/2)=1 
x/2=π/2+2πn 
x2=πn+4πn