2log(7)32-log(7)256-2log(7)14
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Ответил Sro444noo
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2log(7)32-log(7)256-2log(7)14 =
= log(7)32^2-log(7)256-log(7)14^2 =
=log(7) (32^2/(256*14^2)) =
= log(7) 1/94 = log(7) 7^-2 = -2 log(7) 7 = -2 *1 = -2
= log(7)32^2-log(7)256-log(7)14^2 =
=log(7) (32^2/(256*14^2)) =
= log(7) 1/94 = log(7) 7^-2 = -2 log(7) 7 = -2 *1 = -2
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