Question

2cos^2x+2(корня)2sinx-3=0

Answer 1

2(1-sin^2x)+2√2sinx-3=0

2-2sin^2x+2√2sinx-3=0

2sin^2x-√8sinx+1=0

D=8-4*2=0

x= -b/2a = √2/2

sinx= √2/2

x=pi/4+2pik, k∈Z

x=3pi/4+2pik, k∈Z