Question

2а в квадрате-6а+4.5=0

Answer 1

$a^{2}-6a+4,5=0\ a_{1}=-frac{b}{2}+sqrt{b^{2}-c}=-frac{-6}{2}+sqrt{6^{2}-4.5}=3+sqrt{1,5}\ a_{1}=-frac{b}{2}-sqrt{b^{2}-c}=-frac{-6}{2}-sqrt{6^{2}-4.5}=3-sqrt{1,5}$