Question

28/67*(10 целых11/13-2целых11/13:1/2):3целых1/2. 2) (12:3 целых 3/5+2/3):1 целая 1/2-1 целая 1/3

Answer 1

1)    =28/67·(141/13-37/13*2)÷7/2=28/67·(141/13-74/13)·2/7=28/67·67/13·2/7=8/13

2)   =(12÷18/5+2/3)÷3/2-4/3=(12·5/18+2/3)·2/3-4/3=12/3·2/3-4/3=8/3-4/3=4/3