Question

20(d+1,4)=140

$frac{1}{6}$(h-$frac{4}{7}$)=$frac{2}{3}$

$1frac1{3}{4}$*(g-1,2)=5,5
$1frac{2}{3}$*(5x-$frac{1}{2}$)=$frac{7}{9}$

Answer 1

1)

$20(d + 1.4) = 140$

$d + 1.4 = 7$

$d = 7 - 1.4$

$d = 5.6$

2)

$frac{1}{6} (h - frac{4}{7} ) = frac{2}{3}$

$h = frac{4}{7} = 4$

$h = 4 + frac{4}{7}$

$h = frac{32}{7}$

3)

$1 frac{1}{3} 4 times (g - 1.2) = 5.5$

$frac{4}{3} times (g - frac{6}{5} ) = frac{11}{2}$

$frac{4}{3} g - frac{8}{5} = frac{11}{2}$

$40g - 48 = 165$

$40g = 165 + 48$

$40g = 213$

$g = frac{213}{40}$

4)

$1 frac{2}{3} times (5x - frac{1}{2} ) = frac{7}{9}$

$frac{5}{3} times (5x - frac{1}{2} ) = frac{7}{9}$

$frac{25}{3} x - frac{5}{6} = frac{7}{9}$

$150x - 15 = 14$

$150x = 14 + 15$

$150x = 29$

$x = frac{29}{150}$



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