Question

2 завдання, будь-ласкаа

Answer 1

1) f'(x) = -Sinx -Cosx

f'(π/2) = -Sin(π/2) -Cos(π/2) = -1 -0 = -1

2) f'(x) = 2x +1/2√x -2

f'(9) = 2*9 +1/2*3 -2 = 18 +1/6 -2 = 16 +1/6 = 16 1/6