Question

2.Сократите дробь: (-0,4x^2-0,3x+0,7)/(x^2-2x+1)

Answer 1

$frac{-0.4x^2-0.3x+0.7}{x^2-2x+1} = frac{(x-1)(x+1.75)}{(x-1)(x-1)}= frac{x+1.75}{x-1} \ -0.4x^2-0.3x+0.7=0/*10\-4x^2-3x+7=0\4x^2+3x-7=0\D= 9+112=121\ sqrt{D} =11\ x_{1} = frac{-3+11}{8} = frac{8}{8} =1\ x_{2} = frac{-3-11}{8} =- frac{14}{8} =-1.75\ x^{2} -2x+1=(x-1)^2$