Question

( 2-3х)^2=(2-х)(2+х)

Answer 1

${(2 - 3x)}^{2} = (2 - x)(2 + x) \ 4 - 12x + 9 {x}^{2} = 4 - {x}^{2} \ 9 {x}^{2} + {x}^{2} - 12x + 4 - 4 = 0 \ 10 {x}^{2} - 12x = 0 \ 2x(5x - 6) = 0 \ \ 2x = 0 \ x_1 = 0 \ \ 5x - 6 = 0 \ 5x = 6 \ x = frac{6}{5} \ x_2 = 1.2$

Answer 2

Ответ:

Пошаговое объяснение:

( 2-3х)^2=(2-х)(2+х)

4 - 12x + 9x² = 4 - x²

9x² + x² - 12x + 4 - 4= 0

10x²- 12x = 0

2x*(5x - 6) = 0

2x = 0    или  5x - 6 = 0

x = 0               5x = 6

                        x = 6:5

                        x = 1,2

ответ: x₁ = 0 ;       x₂ = 1,2