(2-3cosx)(1+2sinx)=0
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Ответил oganesbagoyan
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(2 - 3cosx)(1+2sinx) =0 ;
[ 2 - 3cosx =0 ;1+2sinx) =0. [ cosx =2/3 ;sinx) = -1/2.
[ x =± arccos(2/3) +2π*k ; x=(-1)^(k+1)* π/6 +π*k ,k∈Z.
ответ : ± arccos(2/3) +2π*k ; (-1)^(k+1)* π/6 +π*k , k∈Z.
[ 2 - 3cosx =0 ;1+2sinx) =0. [ cosx =2/3 ;sinx) = -1/2.
[ x =± arccos(2/3) +2π*k ; x=(-1)^(k+1)* π/6 +π*k ,k∈Z.
ответ : ± arccos(2/3) +2π*k ; (-1)^(k+1)* π/6 +π*k , k∈Z.
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