Question

2 3 2 2 2 3 3х у 5xy​

Answer 1

Объяснение:

$\frac{2}{ {3x}^{2} {y}^{3} } - \frac{3}{ {5x}^{3} {y}^{2} } = \\ \\ = \frac{2 \times 5x}{ {3x}^{2} {y}^{3} \times5x } - \frac{3 \times 3y}{ {5x}^{3} {y}^{2} \times 3y } = \\ \\ = \frac{10x - 9y}{15 {x}^{3} {y}^{3} }$